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definition:Comb(n,k) = (n!)/(k!*(n-k)!)
If a set contains n elements, then there exist Comb(n,k) combinations (subset) containing k elements...from the book 'Probability and Statistics for the engineering, computing and Physical Science' by Edward R. Dougherty, 1990, page 40
! mean faculty: n! = n*(n-1)*(n-2)* ...*3*2*1
ex:Comb(5,2) = (5*4*3*2*1)/(2*1*(3*2*1)) = 120/12 = 10
Your 7 numbers matches GO 7 main numbers
To answer this we must find out how many combinations you can draw 7 number out of 34
comb(34,7) = 34!/[7!*(34-7)!] = 5 379 616
You can chose to play between 5 379 616 different combinations.
Pobability(7+0) = favorable/possible = 1/5 379 616 = 0.0000001858868
You have 0.0000186 % chance of draw 7 out of the 7 main number
favorable = comb(7,6)*comb(2,1) = 7*2=14
possible = comb(34,7) = 5 379 616
Pobability(6+1) = favorable/possible = 14/5 379 616 = 0.0000026024
You have 0.00026 % chance of draw 6 out of 7 main number and 1 out of 2 extra number
favorable = comb(7,6)*comb(34-7-2,1) = 7*25 = 175
Pobability(6+0) = favorable/possible = 175/5 379 616 = 0.00003253
You have 0.0033 % chance of draw 6 out of 7 main number.
favorable = comb(7,5)*[comb(35-7-2,2)*comb(2,0)+comb(35-7-2,1)*comb(2,1)+comb(34-7-2,0)*comb(2,2)]
= comb(7,5)*comb(27,2) = 7371
Pobability(5+0,5+1,5+2) = favorable/possible = 7371/5 379 616 = 0.001370
You have 0.137 % chance of draw 5 out of 7 main number and 0,1 or 2 extra numbers
favorable = comb(7,4)*[comb(2,1)*comb(25,2)+comb(2,2)*comb(25,1)] = 35(2*300+1*25) = 21875
Pobability(4+1,4+2) = favorable/possible = 21875/5 379 616 = 0.004066
You have 0.4066 % chance of draw 4 out of 7 main number, and
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If you are interested in playing poker on the internet, I recomend Everest Poker. By signing up with Everest Poker you get an USD 100 welcome bonus. I highly recommends this site where there is an excellent selection of tables and an unusually high proportion of fish (weak players)! |